Pls help! Will mark Branliest!! 50 points for whoever answers!!!!!!

Answer: See below
Step-by-step explanation:
Isolate x for x-2y+2z=9
3x=9+2y
[tex]x=\frac{9+2y}{3}[/tex]....(1)
Substitute (1) into the 2nd equation
[tex]\begin{bmatrix}-\frac{9+2y}{3}+3y=-4\\ 2\cdot \frac{9+2y}{3}-5y+3z=16\end{bmatrix}[/tex]
[tex]\frac{3\left(-9+7y\right)}{3}=3\left(-4\right)[/tex]
7y=-3
y=-3/7
Substitute y=-3/7
[tex]\begin{bmatrix}3z+\frac{18-11\left(-\frac{3}{7}\right)}{3}=16\end{bmatrix}[/tex]
[tex]\begin{bmatrix}3z+\frac{53}{7}=16\end{bmatrix}[/tex]
Isolate z by substituting it
[tex]3z+\frac{53}{7}=16[/tex]
[tex]\frac{3z}{3}=\frac{\frac{59}{7}}{3}[/tex]
[tex]z=\frac{59}{21}[/tex]
For x =9+2y/3 substitute z=59/21 and y=-3/7
[tex]x=\frac{9+2\left(-\frac{3}{7}\right)}{3}[/tex]
[tex]x=\frac{19}{7}[/tex]
[tex]x=\frac{19}{7},\:z=\frac{59}{21},\:y=-\frac{3}{7}[/tex]
Answer:
(1, - 1, 3 )
Step-by-step explanation:
x - 2y + 2z = 9 → (1)
- x + 3y = - 4 → (2)
2x - 5y + 3z = 16 → (3)
Add (1) and (2) term by term to eliminate x
y + 2z = 5 → (4)
Multiply (2) by 2
- 2x + 6y = - 8 → (5)
Add (3) and (5) term by term to eliminate x
y + 3z = 8 → (6)
Subtract (6) from (4) term by term to eliminate y
- z = - 3 ( multiply both sides by - 1 )
z = 3
Substitute z = 3 into (4)
y + 2(3) = 5
y + 6 = 5 ( subtract 6 from both sides )
y = - 1
Substitute y = - 1, z = 3 into (1) and solve for x
x - 2(- 1) + 2(3) = 9
x + 2 + 6 = 9
x + 8 = 9 ( subtract 8 from both sides )
x = 1
solution is (1, - 1, 3 )